Pls asap
let line l1 be the graph of 5x + 8y = -9. line l2 is perpendicular to line l1 and passes through the point (10,10). if line l2 is the graph of the equation y=mx +b, then find m+b.

The slope of line L1 is 5/8, so the slope of L2 is -8/5.  We are also told that the line passes through (10,10), so by point-slope form, the equation of the line is y - 10 = -8/6*5(x - 10).  This simplifies to y = -8/5*x + 26.

a c

step-by-step explanation:

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: