Arectangular sheet of cooper is twice as long as it is wide. from each corner a 3-inch square is cut out, and the ends are then turned up to form a tray. if the volume of the tray is 324 cubic inches , what were the original dimensions of the sheet of cooper?

length=24 inches and width=12 inches

Step-by-step explanation:

Let width of the rectangular sheet be x.

Then its length is twice as width = 2x

From each corner 3-inch square is cut to form a tray.

The length of the tray formed = l = 2x-6 (total length - length of 2 squares cut out from both ends)

The width of the tray formed  = b = x-6 (total width - length of 2 squares cut out from both ends)

Height of the tray formed = h = 3 inches

Volume of the tray = l*b*h = (2x-6)*(x-6)*3 = 324 cubic inches.

The length and width of the sheet is 24 and 12 inches respectively.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.