Planet krypton has 2 times the radius and 2 times the mass of the earth. what is the best estimate for the magnitude of the gravitational field at the surface of planet krypton in m/s2?
a. 20m/s^2
b. 10m/s^2
c. 5m/s^2
d. 2.5m/s^2

9514 1404 393

  C.  5 m/s^2

Step-by-step explanation:

The force due to gravity is proportional to the mass and inversely proportional to the square of the radius. So, Krypton's gravity in relation to Earth's is ...

  (2)/(2^2) = 1/2

Earth's surface acceleration due to gravity is about 10 m/s^2, so 1/2 that is about 5 m/s^2. (Choice C)

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!