[40 points]

find the area of the shaded region.
enter a decimal rounded to the nearest tenth.

a = __ cm^2

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- First find the area of the whole circle

The equation is :

πr^2

Substitute the radius in:

π(5)^2

Solve:

Area of full circle = 25π

(Note : leave this answer in terms of 'pi' so it is easier to handle

Next, find the area of the sector

The equation for this is:

(angle/360) x πr^2

Substitute the values in:

(80/360) x π(5)^2

Solve :

Area of sector = (50/9)π

Now, find the area of the triangle:

1/2 absinC

Substitute the values in:

1/2(5)(5) x sin(80) = 12.31009691

Subtract this answer from the area of the sector

Answer = 5.14319607

Subtract this from the area of the whole circle

Answer = 73.39662073

To the nearest tenth, that would be 73.4 cm^2

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- Ally ✧

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The area of shaded region is 61.4cm²

Step-by-step explanation:

Convert ° to π :

(80/180)° × π

= (4/9)π

A = (1/2)×5²×[(4/9)π - sin(4/9)π]

= 17.14cm² (not shaded region)

Area of circle = πr²

A = π×5²

=25π cm²

Area of shaded = Area of circle - Area of not shaded region

A = (25π - 17.14)cm²

= 61.4cm² (near. tenth)

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct