Find the center of the circle that can be circumscribed about abc with a(0,0) b(6,0) c(6,4)

This can be solved by the distance formula.
If the center of the circle is at (h,k)
r² = (h - 0)² + (k - 0)²
r² = (h - 6)² + (k - 0)²
r² = (h - 6)² + (k - 4)²

Equating the equations
h² + k² = (h - 6)² + k²
h = 3

(h - 6)² + k² = (h - 6)² + (k - 4)²
k = 2

Therefore, the center of the circle is at (3,2).

Cis your correct answer

The correct answer is addition