Mathematics, 14.12.2019 22:31 maggie9459
Denise needs to move some bags of gardening soil from her garage to her mother’s garden. the topsoil weighs 30 pounds per bag, and the mulch weighs 30 pounds per bag. the wagon she is using carries a maximum of 330 pounds. the table shows the first three loads of topsoil and mulch she has carried in the wagon. topsoil, t (pounds) 7 2 3 mulch, m (pounds) 3 6 8 write a linear inequality to describe the bags of topsoil and mulch the wagon can carry at one time.
Answers: 3
Mathematics, 20.06.2019 18:04
Alarge rectangle is divided into four smaller rectangles.
Answers: 1
Mathematics, 21.06.2019 17:10
Determine whether the points (–3,–6) and (2,–8) are in the solution set of the system of inequalities below. x ? –3 y < 5? 3x + 2 a. the point (–3,–6) is not in the solution set, and the point (2,–8) is in the solution set. b. neither of the points is in the solution set. c. the point (–3,–6) is in the solution set, and the point (2,–8) is not in the solution set. d. both points are in the solution set.
Answers: 3
Mathematics, 21.06.2019 19:00
What are the solutions of the system? solve by graphing. y = -x^2 -6x - 7 y = 2
Answers: 2
Mathematics, 21.06.2019 19:30
Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.
Answers: 3
Denise needs to move some bags of gardening soil from her garage to her mother’s garden. the topsoil...
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