What is a value after 7 years of a car that originally cost $25000 if it depreciates at a rate of 8% per year

original cost times 8%

$25,000 x .08 = $2,000

then take $25,000 - $2,000 = $23,000 (first year depreciation)

continue with 2nd year

$23,000 x .08 = $1840

23000-1840 = 21160 (2nd year depreciation)

21160 x .08 = 1693

21160 - 1693 = 19467 (3rd year depreciation)

19467 x .08 = 1557

19467 - 1557 = 17910 (4th year depreciation)

17910 x .08 = 1433

17910 - 1433 = 16477 (5th year depreciation)

16477 x .08 = 1318

16477 - 1388 = 15159 (6th year depreciation)

15159 x .08 = 1213

15159 - 1213 = 13946 (7th year depreciation)

Step-by-step explanation:

Asset Value x Annual Percentage  = Depreciation Amount

Asset Value - Depreciation Value  = Balance

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !