Find b and s. at the present time mrs. b's age is six years more than four times her sons age. three years ago she was seven times as old as her son was then

Mrs. B's age = y = 38 years

her son's age = x = 8 years

Step-by-step explanation:

To Find:

Mrs. B's age = y =?

her son's age = x = ?

Solution:

Let Mrs. B's age  be 'y' years

and her son's age be 'x' years

Three years ago Mrs B's will be (y - 3) and her son's age will be (x - 3)

According to the first given condition,

y = 6 + 4x ...............Equation ( 1 )

According to the second given condition,

(y - 3 ) = 7 (x - 3 )..........Equation ( 2 )

equating equation 1 in equation 2 we get

6 + 4x -3 = 7x - 21

7x - 4x = 21 + 3

∴

Now substitute x in equation 1 we get

y = 6 + 4×8

y = 6 + 32

∴ y = 38 years

Mrs. B's age = y = 38 years

her son's age = x = 8 years

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )