Graphing in point-slope form y−y1=m(x−x1)

graph the equation y+7=−45(x−4) ?

Step-by-step explanation:

The point-slope form of an equation of a line:

m - slope

(x₁, y₁) - a point on a line

The slope-intercept form of an equation of a line:

m - slope

b - y-intercept → (0, b)

We have the equation in a point-slope form:

Therefore we have one point: (4, -7).

Convert to the slope-intercept form:

             use the distributive property

         subtract 7 from both sides

Put x = -1 to the equation:

Therefore we have the second point (-1, -3).

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

because i took test