Plz hurry it's

you randomly draw marbles from a bag containing both blue and green marbles, without replacing the marbles between draws. if b=drawing a blue marble and g=drawing a green marble, which represents the probability of drawing a blue marble first and a green marble second?

a. p(b)⋅p(g)

b. p(b and g)

c. p(g after b)

d. p(b, then g)

The correct option is

(D) P(B, then G).

Step-by-step explanation:  Given that we  randomly draw marbles from a bag containing both blue and green marbles, without replacing the marbles between draws.

Also, B = drawing a blue marble and G = drawing a green marble.

We are to select the option that represents the probability of drawing a blue marble first and a green marble second.

Since we are drawing the second marble without replacing the first drawn marble, so the event is of the form

"first, then second."

So, the probability is written as P(B, then G).

Thus, The required probability is P(B, then G).

Option (D) is CORRECT.

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.