At a market, a kiwi costs $1, and an apple costs $1.50. if charlie bought 5 more apples than kiwis and spent $12.50, how many apples did he buy? how many kiwis?

Number of apples bought = 7 and Number of kiwis bought = 2

Let "k" be the number of kiwi bought

Let "a" be the number of apples bought

At a market, a kiwi costs $1, and an apple costs $1.50

Cost of each kiwi = $ 1

Cost of each apple = $ 1.50

If Charlie bought 5 more apples than kiwis and spent $12.50

Apples bought = 5 + kiwis

a = 5 + k  --------- eqn 1

Also he spent $ 12.50

Number of apples bought x Cost of each apple + number of kiwi bought x Cost of each kiwi = 12.50

1.5a + k = 12.50 --------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "k"

Substitute eqn 1 in eqn 2

1.5(5 + k) + k = 12.5

7.5 + 1.5k + k = 12.5

7.5 + 2.5k = 12.5

2.5k = 5

Therefore from eqn 1,

a = 5 + k = 5 + 2 = 7

Summarizing the results:

Number of apples bought = 7

Number of kiwis bought = 2

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,