Through (-2, -3), perp. to y = x- 2/1

The equation of line passing through point ( - 2 , - 3 ) and slope 1 is          y = x - 1

Step-by-step explanation:

Given equation of line as :

y = x -

i.e y = x - 2

The standard equation of line is given as

y = m x + c ,

where m is the slope of the line and c is the y-intercept

Now, comparing the line , we have

Slope = m = 1

Now, The other line is perpendicular to the first line

So, from perpendicular property of line

The product of their slope = - 1

Let The slope of other line = M

So,  m × M = - 1

Or,  ( - 1 ) × M = - 1

or M =

∴  M = 1

So , The slope of other line = M = 1

∵ The other line is passing through point ( x , y ) =  ( - 2 , - 3 )

Now, satisfying the points and slope with standard line equation

I.e y = M x + c

or, - 3 = 1 × ( - 2 ) + c

or, -3 = - 2 + c

or, - 3 + 2 = c

∴  c = - 1

So, The intercept of other line = c = - 1

Now The equation of line with slope intercept

y = 1 × x + ( - 1 )

Or, y = x - 1

Hence The equation of line passing through point ( - 2 , - 3 ) and slope 1 is  y = x - 1       Answer

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

answer: plz put a pic in so i can answer it

step-by-step explanation: