Suppose that p0 is invested in a savings account in which interest is compounded continuously at 6.6% per year. that is, the balance p grows at the rate given by the following equation. dp/dt - = 0.066p(t)
a) find the function p(t) that satisfies the equation. write it in terms of p0 and 0.066.
b) suppose that $1000 is invested. what is the balance after 2 years?
c) when will an investment of $1000 double itself?
a) choose me correct answer below.
a) p(t) = p 0 e 0066t
b) p(t) = 0.066p 0 et
c) p(t) = p(t)e 0 066t
d) p(0) = p(t)e 0066t
b) the balance after 2 year is $ . (type an integer or decimal rounded to two decimal places as needed.)
c) the doubling time is year. (type an integer or decimal rounded to two decimal places as needed.)