Given: segment ac is perpendicular to segment bd prove: δacb ~ δecd reflect δecd over segment ac. this establishes that ∠acb ≅ ∠e'c'd'. then, this establishes that therefore, δacb ~ δecd by the aa similarity postulate. translate point e' to point a; ∠e'd'c' ≅ ∠abc translate point d' to point a; ∠e'd'c' ≅ ∠bac translate point d' to point b; ∠d'e'c' ≅ ∠bac translate point e' to point a; ∠d'e'c' ≅ ∠bac

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

more detail

step-by-step explanation:

idk wbu

step-by-step explanation:

you should talk someone who owns the website about it. you did not deserve to have all that hard work and time taken away. id watch videos of little puppies to cool you down, and maybe some nacho cheese doritos.