The angle of elevation of the top of a tower from a point on the ground is 50 degrees. after moving 50 meters away from the tower, the angle of elevation reduced to 40 degrees. find the height of the tower?

The height of the tower is 141.74 meters.

Step-by-step explanation:

See the attached diagram.

Let the position of the tower os AB with A as the base and B is the top.

Now, angle of elevation of point B from point C is 50°, and the from point D is 40°, and hence, CD = 50 meters,

Now, from Δ ABC,

⇒ .......... (1)

Again, from Δ ABD,  

⇒ .......... (2)

Now, DC = AD - AC  

⇒ 50 = 1.192x - 0.839x

⇒ 50 = 0.353x

⇒ x = 141.74 meters.

Hence, the height of the tower is 141.74 meters. (Answer)

answer: a. 74

step-by-step explanation:

it shows divided evenly, so add the 37+37 = 74

1/4 and 8/3 because:

the reciprocal if 4 is 1/4 because 4 is used as 4/1 and the opposite of that is 1/4. the opposite of 3/8 is 8/3 so that is the answer.