An architect designed this scale model of a warehouse for a building contractor.

if w = 13 ft, x = 23 ft, y = 19 ft, and z = 15 ft, what is the area of the warehouse?
a. 80 sq ft
b. 437 sq ft
c. 413 sq ft
d.
608 sq ft

tl;dr Answer is C

Here we will have to calculate 3 different areas separately.

When calculating the area of the triangle we will use the formula

A = (h*b)/2  

A = Area

h = height

b = base

To find the height we do X - Z  

23 - 15 = 8 ft

To find the base we do Y - W

19 - 13 = 6 ft

Using the formula above we can now solve for A  

A = (8*6)/2

A = (48)/2

A = 24 sq ft

Now we solve the two rectangles using the formula  

A = wl

w = width

l = length

We will calculate the area of the left most rectangle first.

We know the length of the rectangle because it's Y - W and we are given the width of the triangle.

w = 15 ft

l = 6 ft

A = 15*6

A = 90 sq ft

Second Rectangle has the width of X and length of W

w = 23 ft

l = 13 ft

A = 23 * 13

A = 299 sq ft

Now we add all the areas to give us the total area of the warehouse.

24 + 90 + 299 = 413 sq ft

Therefore, the answer is C

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer

both equations and proportions are better.