In a group of 191 students, 10 are taking french, business and music, 36 are taking french and business, 20 are taking french and music, 18 are taking business and music, 65 are taking french, 76 are taking business, and 63 are taking music (note that each of the above groups may also take other subjects). let f, b, m be the sets of students taking at least french, business, or music, respectively (i. e. that subject and possibly, but not necessarily, others). find the number of students in the set f4b4m.

Correct question: Find the number of students in the set  FΔBΔM

FΔBΔM = 130

Step-by-step explanation:

In set notation the symbol Δ means symmetric difference. The symmetric difference of two or more sets is the combination or union of the elements of the sets excluding their interception.

in the question the following are given;

n(F∩B∩M)=10

n(F∩B)=36

n(F∩M)=20

n(B∩M)=18

n(F)=65

n(B)=76

n(M)=63

From the attached Venn diagram,

FΔBΔM= 35+32+19+26+10+8

FΔBΔM= 130

you answer is a

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.