Matt and trey are remodeling their gardens. matt purchased 8 ferns and 1 rosebush for $35. trey purchased 4 ferns and 3 rosebushes for $25. determine the price of each plant.

Step-by-step explanation:

If we let f and r represent the costs of a fern and a rosebush, respectively, we can write equations that represent each of the purchases:

  8f +r = 35 . . . . Matt's purchase

  4f +3r = 25 . . . . Trey's purchase

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We can solve these equations using "elimination." We note that the coefficient of f in the second equation is half that in the first equation.

Subtracting the first equation from twice the second, we get ...

  2(4f +3r) -(8f +r) = 2(25) -(35)

  5r = 15 . . . . . simplify

  r = 3 . . . . . . . divide by 5

Substituting into the first equation, we have ...

  8f + 3 = 35

  8f = 32 . . . . . . subtract 3

  f = 4 . . . . . . . .  divide by 8

The fern costs $4; the rosebush costs $3.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the answer is y = 11.54

hope this : )