6. e1 and e2 are events from the same sample space; p(e1)=0.37, p(e2)=0.45, and p(e1, e2)=0.14. a. find the probability that e2 does not occur. b. find the probability that either e1 or e2 occurs. c. find the probability that neither e1 nor e2 occurs.

a. 0.55

b. 0.68

c. 0.18

Step-by-step explanation:

a. The probability that E2 does not occur is one minus the probability that E2 occurs:

b. The probability that either E1 or E2 occurs is given by the sum of their individual probabilities minus their joint probability:

c. The probability that neither E1 nor E2 occurs is one minus the probability of E1 occurring minus the probability of E2 occurring:

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.