Celeste is making fruit baskets for a local hospital. the directions say to use 5 apples for every 6 oranges. celeste is filling her baskets with 2 apples for every 3 oranges. complete the tables to find equivalent ratios. circle two columns, one in each table, in which the number of oranges is the same.

apples 5 apples 2
oranges 6 oranges 3

A. Equivalent ratios of 5:6

We multiply both the numerator and the denominator by the same number, this way:

10:12 , 15:18, 20:24, 25:30

B. Equivalent ratios of 2:3

We multiply both the numerator and the denominator by the same number, this way:

4:6 , 6:9, 8:12, 10:15, 12:18

C. We have the same number of oranges at:

10:12 and 8:12

15:18 and 12:18

Like Celeste decided not to follow the directions, she's actually using less apples than expected to fill the baskets.

Step-by-step explanation:

1. Let's check all the information provided to answer the question correctly:

Ratio that the local hospital say to Celeste to use : 5 apples for every 6 oranges

Ratio that Celeste is actually using: 2 apples for every 3 oranges

2.  Complete the tables to find equivalent ratios.

A. Equivalent ratios of 5:6

We multiply both the numerator and the denominator by the same number, this way:

10:12 , 15:18, 20:24, 25:30

B. Equivalent ratios of 2:3

We multiply both the numerator and the denominator by the same number, this way:

4:6 , 6:9, 8:12, 10:15, 12:18

3. Circle two columns, one in each table, in which the number of oranges is the same.

We have the same number of oranges at:

10:12 and 8:12

15:18 and 12:18

Like Celeste decided not to follow the directions, she's actually using less apples than expected to fill the baskets.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: