If tan theta= -3/4 and θ is in quadrant iv, cos2 theta= and tan2 theta= .

let's recall that the angle θ is in the IV Quadrant, meaning the x/adjacent is positive whilst the y/opposite is negative, thus

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

answer: hey there,

the answer you are looking for is a..

hope this you!