Last year it was found that on average it took students 20 minutes to fill out the forms required for graduation. this year the department has changed the form and asked graduating student to report how much time it took them to complete the forms. of the students 22 replied with their time, the average time that they reported was 18.5 minutes, and the sample standard deviation was 5.2. can we conclude that the new forms take less time to complete than the older forms?

If we compare the p value and a significance level assumed we see that so we can conclude that we FAIL to reject the null hypothesis, and the actual true mean for the time is not significantly less than 20 minutes at 5% of significance.  

Step-by-step explanation:

Data given and notation  

represent the sample mean  

represent the standard deviation for the sample

sample size  

represent the value that we want to test  

represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean for the new forms take less time to complete than the older forms, the system of hypothesis would be:  

Null hypothesis:  

Alternative hypothesis:  

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

(1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

Now we need to find the degrees of freedom for the t distirbution given by:

What do you conclude?

Compute the p-value

Since is a one left tailed test the p value would be:  

If we compare the p value and a significance level assumed we see that so we can conclude that we FAIL to reject the null hypothesis, and the actual true mean for the time is not significantly less than 20 minutes at 5% of significance.  

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.