The area of a rectangle is 108 in^2 . if the length is 12 inches longer then the width, find the dimensions of the rectangle

The length and width of rectangle are 18 inches and 6 inches respectively

Given that area of rectangle is 108 square inches

Let "L" be the length of rectangle

Let "W" be the width of rectangle

To find: dimenions of rectangle. i.e length and width

Given that length is 12 inches longer then the width

Length = 12 + width

L = 12 + W

The area of rectangle is given as:

Substituting the given values in above formula,

Let us solve the above quadratic equation using quadratic formula

Substituting the values in quadratic formula,

Since width cannot be negative, ignore negative value

So width of rectangle = 6 inches

L = 12 + W = 12 + 6 = 18 inches

So the length and width of rectangle are 18 inches and 6 inches respectively

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right