Aset of x and y scores has a regression equation with a slope of b = 4. if the mean for the x values is mx = 2 and the mean for the y values is my = 6, what is the y-intercept value for the regression equation?

The Y-intercept value for the regression equation is -2

Step-by-step explanation:

The linear regression has the form: y = a + b*x, where a is the Y-intercept and b is the slope. To find the a compute the following:

a = MY - b*MX

where MX and MY denotes mean for the X and the Y respectively. Replacing:

a = 6 - 4*2 = -2

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: