At a local fitness center, members pay aa $14 membership fee and $4 for each aerobics class. nonmembers pay $6 for each aerobics class. for what number of aerobics classes will the cost for members and nonmembers be the same?

The number of aerobics classes for which the cost for members and nonmembers be same is 7 classes  .

Step-by-step explanation:

Given as :

The cost for membership fee = $ 14

The cost for aerobics class for members = $ 4

The cost for aerobics class for nonmembers = $ 6

Let The number of aerobics classes for which the cost for members and nonmembers be same = n classes

So, According to question

The cost for membership fee + ( The cost for aerobics class for members ×  The number of aerobics classes ) = The cost for aerobics class for nonmembers

I.e $ 14 + ( $ 4 × n ) = $ 6 × n

Or, 14 = 6 × n - 4 × n

or, 14 = 2 × n

∴  n =

I.e n = 7

So, The number of aerobics classes for which the cost for members and nonmembers be same = n = 7 classes

Hence , The number of aerobics classes for which the cost for members and nonmembers be same is 7 classes  . Answer

(2,6)

step-by-step explanation:

cause i just did this and got the answer

you're welcome

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)