Trigonometry: solve for x: cosxββ3 /4 sin(2x)=0
i got -2/β3 and 2β3 /3.
i...
Mathematics, 10.12.2019 11:31 sports1997
Trigonometry: solve for x: cosxββ3 /4 sin(2x)=0
i got -2/β3 and 2β3 /3.
i don't think i did it right. in advance!
Answers: 1
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