Billy jo's school is selling tickets to a fall festival. on the first day of ticket sales the school sold 3 adult ticket and 8 student tickets for a total of $72. the school took in $152 on the second day by selling 7 adult tickets and 16 student tickets. how much is a student ticket?

Y = 6

Step-by-step explanation:

On the first day of ticket sales the school sold 3 adult ticket and 8 student tickets for a total of $72. The school took in $152 on the second day by selling 7 adult tickets and 16 student tickets. How much is a student ticket?  

Day 1: 3x + 7y = 72

Day 2: 7x + 16y = 152

This becomes a system of equations.

3x+8y=72

3x+8y+−8y=72+−8y (Add -8y to both sides)

3x=−8y+72

3x/3 =  −(8y+72)/3

X = (-8/3) y + 24

Substitute  (-8/3) y + 24 for x in7x+16y=152:

7(-8/3 y + 24) + 16y = 152

-8/3 y + 168 = 152 (Simplify both sides of the equation)

-8/3 y + 168 − 168 = 152 + (−168) (Add -168 to both sides)

-8/3 y = -16

(-8/3 y)/(-8/3 y) = -16/ -8/3 y (Divide both sides by (-8)/3)

y = 6

If you wanted to keep going...

Substitute 6f or y in x = (-8/3) y + 24

(-8/3) y + 24  =  (-8/3) (6) + 24

SImplify: x = 8

X = 8 and Y = 6

Hope this helps! ♥

~A.W.E.S.W.A.N~

idk

step-by-step explanation:

i don't know

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204