In a princeton survey of 800 randomly selected teens, 272 of them admitted to texting while driving. obtain a 95% confidence interval for the proportion of teens who text while driving.

The 95% confidence interval would be given (0.307;0.373).

Step-by-step explanation:

Data given and notation  

n=800 represent the random sample taken    

X=272 represent the teens who admit texting while driving

 proportion estimated for teens who admit texting while driving

represent the significance level (no given, but is assumed)    

Confidence =0.95 or 95%

p= population proportion of teens who admit texting while driving

The confidence interval for the population proportion would be given by this formula:

For the 95% confidence interval the value of and , with that value we can find the quantile required for the interval in the normal standard distribution.

And replacing into the confidence interval formula we got:

And the 95% confidence interval would be given (0.307;0.373).

We are confident (95%) that about 30.7% to 37.3% of the teens are texting while driving

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!

answer: median

step-by-step explanation:

the median is the middle value when a data set is ordered from least to greatest