To assess the accuracy of a kitchen scale a standard weight known to weigh 1 gram is weighed a total of n times and the mean, , of the weighings is computed.

suppose the scale readings are normally distributed with unknown mean, µ, and standard deviation = 0.01 g.

how large should n be so that a 90% confidence interval for µ has a margin of error of ± 0.0001?

27061

Step-by-step explanation:

Given : The scale readings are Normally distributed with unknown mean, µ, and standard deviation g.

Confidence interval = 90%

We know that the critical value for 90% confidence interval = z*=1.645 (by z-table)

Margin of error E= ± 0.0001

Now, Required minimum size : n=

Hence, n= 27061.

f(x)=2/3x+4/3 is the answer because is whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation: