At a college bookstore, kyle purchased a textbook and a calculator that cost a total of $94, not including tax. the price of the
textbook, t, is $10 less than 3 times the price of the calculator, c. based on these cost, what was the cost of the textbook?
a)
$21
$26
c)
568
d)
$78

$68 option C

Step-by-step explanation:

Lets use equations to show this problem.  First, Kyle bought two items, a calculator at a price c and a textbook at a price t and paid $94. So:

c + t = 94 [equation 1] (I will omit $ symbol from now for simplicity)

Then we know that the textbook costs $10 less than the triple of the calculator price. In equation this is:

t = 3c - 10 [equation 2]

Now, replace equation 2 in equation 1:

c + t = c + 3c -10 = 4c -10

4c - 10 = 94

Sum 10 in both sides:

4c -10 + 10 = 94+10

4c = 104

Divide both sided by 4:

4c/4 = 104/4

c = 26

So, calculator price is $26

Replace this value in equaiton 2 (or in equation 1) to find t:

t = 3(c) -10

t = 3*26 -10

t = 78 -10

t = 68

Thus, the textbook costs $68

The correct option is C) assuming you typed wrongly and in the place of the 5 goes a $ symbol.

it is true

step-by-step explanation:

all the combinations add up i used   calculator