find the value of k so that the solution set for the following equation is -7.
3x - 4 - 5(x-2) = 3/4x + 1/3 - k

k = -299/12 = - 24 11/12

Step-by-step explanation:

3x - 4 - 5(x-2) = 3/4x + 1/3 - k

x = - 7

3*(-7) - 4 - 5(-7 -2) = 3/4*(-7) + 1/3 - k

-21 -4 -5*(-9) = - 21/4 + 1/3 - k

-25 + 45 = - 21/4 + 1/3 - k

20 = (- 21*3)/(4*3) + 4/(3*4)  - k

20 = - 63/12 + 4/12 - k

20 = - 59/12 - k

k = - 59/12 - 20

k = -299/12 = - 24 11/12

6hryt%4578855

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.