Write an equation in slope-intercept form for the line with y-intercept of 7 and slope of 1/4
explain how you figured it out because i want to learn how to do it not just the

y=1/4x + 7

Step-by-step explanation:

In the equation y=mx+b, the m is the slope of the line (rise over run) and the b is the y-intercept (where the line crosses the y-axis).

if the slope is negative, the equation is y= -x + b. If the y-intercept is 0, the equation is y = mx

slope intercept form is y=mx+b

Step-by-step explanation:

y=1/4x+7. remember the m is slope next to the x and the y is place of the b

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

1/4 because there is 4 grades.