What two number multiply to -132 and add to -1

The two numbers can be -12 and 11, or 11 and -12.

Step-by-step explanation:

xy=-132

x+y=-1

x=-1-y

(-1-y)y=-132

-y-y^2=-132

-y^2-y-(-132)=0

-y^2-y+132=0

y^2+y-132=0

factor out the trinomial,

(y-11)(y+12)=0

zero property,

y-11=0, y+12=0,

y=0+11=11,

y=0-12=-12

x+11=-1 & x+(-12)=-1

x=-1-11=-12

x=-1-(-12)=-1+12=11

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3