Aball is thrown from a height of 45 meters with an initial downward velocity of 10 m/s. the ball's height h (in meters) after t seconds is given by the following. h=45-10 t- 5 t^2. how long after the ball is thrown does it hit the ground?

2.16 s

Step-by-step explanation:

When it hits the ground, height h=0 hence

Using quadratic formula

Since time can't be negative,

t=2.16 s

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180