Na simple random sample of 219 students at a college, 73 reported that they have at least $1000 of credit card debt.

which interval is the 99% confidence interval for the percent of all the students at that college who have at least $1000 in credit card debt?

(31.0 ,35.6)

( 30.1 , 36.5)

(25.0 ,41.6)

(27.5 ,39.1 )

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540

3 is greater then both of those numbers

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step-by-step explanation:

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