Solve
write the equation of the line passing through the points (0, -4) and (-2, 2).

write the equation of the line passing through the points (-6,1) and (-4,2).

Question 1:

y-2=-3(x+2) - In Point-Slope Form

y=-3x-4 - In Slope-Intercept Form

Question 2:

y-1=1/2(x+6) - In Point-Slope Form

y=1/2x+4 - In Slope-Intercept Form

Step-by-step explanation:

Attached is a picture of the point slope formula which we will be using to write the equations of these lines...

Question 1: Write the equation of the line passing through the points (0, -4) and (-2, 2).

1) First, we need to find the slope, or "m" of this line. Lets plug these two points into slope formula (y2-y1/x2-x1):

(2--4)/(-2-0)

2) Simplify:

6/-2

3) Solve:

m=-3

4) Now, lets plug that slope into point-slope formula along with a set of points that were given to us [I will be using (-2,2)]

y-2=-3(x+2)

5) Now, if you wish to write the equation of the line in slope intercept form, we will have to do some simple algebra. First, distribute -3 to x and 2:

y-2=-3x-6

6) Next, Add 2 to both sides: (Now it is in slope-intercept form)

y=-3x-4

Question 2: Write the equation of the line passing through the points (-6,1) and (-4,2).

1) First, we need to find the slope, or "m" of this line. Lets plug these two points into slope formula (y2-y1/x2-x1):

(2-1)/(-4--6)

2) Simplify:

m=1/2

3) Now, lets plug that slope into point-slope formula along with a set of points that were given to us [I will be using (-6,1)]

y-1=1/2(x+6)

4) Now, if you wish to write the equation of the line in slope intercept form, we will have to do some simple algebra. First, distribute 1/2 to x and 6:

y-1=1/2x+3

5) Next, add 1 to both sides: (Now it is in slope-intercept form)

y=1/2x+4

1,918

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841