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what is the average rate of change of the function on the interval from x = 1 to x = 2?

f(x)=10(5.5)^x
enter your answer, as a decimal, in the box.

The equation to calculate the average rate of change is: y/x

Step-by-step explanation:

y = f(x2) - f(x1)

x = x2 - x1

x1: 1 (The smaller x value. It can be any number)

x2: 2 (The larger x value. It also can be any number)

f(x1): The value when you plug x1 into the function.

f(x2): The value when you plug x2 into the function.

If we know this, the variables for this problem are assuming the function is 10(5.5)^x:

x2: 2

x1: 1

f(x2): 10(5.5)^(2) = 302.5

f(x1): 10(5.5)^(1) = 55

This means:

y = 302.5  - 55 = 247.5

x = 2 - 1 = 1

Remember: the equation for avg rate of change is y/x

So, our average rate of change for the function on the interval [1,2] is 247.5 (y/x = 247.5/1)

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

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