When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. when a certain constant force acts upon an object with mass 6 kg, the acceleration of the object is 7 /ms2. if the same force acts upon another object whose mass is 14 kg, what is this object's acceleration?

a = 3 m/s^2

Step-by-step explanation:

Let the acceleration of the object be represented by a

Let the constant force acting on the object be represented by k

Let the mass of the object represented by m

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. This means that

a = k/m

When a certain constant force acts upon an object with mass 6 kg, the acceleration of the object is 7 /ms2. It means that when a = 7, m = 6. We would find k. Therefore

7 = k/6

k = 7×6 = 42

The expression becomes

a = 42/m

If the same force acts upon another object whose mass is 14 kg, it means that m = 14, then

a = 42/14 = 3

ljn

step-by-step explanation: