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a chemist needs to mix an 20% acid solution with a 50% acid solution to obtain 15 liters of a 34% acid solution. how many liters of each of the acid solutions must be used?

14

Step-by-step explanation:

Step-by-step explanation:

We are mixing two acids.

x = liters of 20% acid solution

y = liters of 70% acid solution

x + y = 8    This represents the total number of liters

and

.2x + .7y = .5(8)   This represents the concentration of the solutions

Since x+y=8, y = 8-x

We can use substitution.

.2x + .7(8-x) = 4

.2x + 5.6 - .7x = 4

Combining like terms

-0.5x = - 1.6

Dividing by -0.5

x = 3.2

There are 3.2 liters of the 20% solution to be mixed with 4.8 liters of the 70% solution.

∈3,600

step-by-step explanation:

step-by-step explanation:

6