Ineed with question 3 b-d, i figured out the previous questions but i somehow cant figure the rest out. is there anybody that could me with it?

may i get reply by sunday before midnight, you kind students of

3. b) y = (1/2)x + 1

3. c) y = -2x

3. d) y = -2x + 3

Step-by-step explanation:

The equation of a line is y = mx + b.

x and y are points on the graph.

m is the slope.

b is the y-intercept.

When a slope is negative, it is a negative value (like -1, -7 or -2/3). When a slope is positive, it is a positive value (like 1, 7 or 2/3).

When a line is steep, is has a greater slope and a greater slope value in an equation. (Think about hiking: a steeper hill is harder to climb. The floor is least steep with a slope of about 0.)

The y-intercept occurs when x = 0. On a graph, the line hits the y-axis.

In the equation y = x, the slope is 1.

3. b

The slope is half as that of the line y = x. Half of 1 is 1/2.

m = 1/2  <=this number is positive already

We know the y-intercept is 1 because x=0 in the point.

Put the slope and y-intercept back into the equation:

y = (1/2)x + 1

3. c

The slope is twice as that of the line y = x. Double of 1 is 2.

m = 2  <=this number needs to be negative. m = -2

We know the y-intercept is 0 because x=0 in the point. We do not need to write the y-intercept if it's 0.

Put the slope into the equation:

y = -2x

3. d

The slope is half as that of the line y = x. Half of 1 is 1/2.

m = 1/2  <=this number needs to be negative. m = -1/2

The given point, (0,3), shows the y-intercept is 3 because x = 0.

Put the slope and y-intercept back into the equation:

y = -2x + 3

whats the