Atriangle has side lengths of 7 in., 9 in., and 11.
determine whether this is a right triangle and why

no

Step-by-step explanation:

because when you Multiply 7 to the power of 2 its automatically greater than the actual answer and obviously the 9 to the power of 2 already is a lot greater than 11 times 11.

It is not a right triangle because the other side is 11 and not 11.40  when we apply the Pythagoras theorem rule on it

Step-by-step explanation:

To determine whether it is a right triangle, all we simply need to do is to check using the Pythagoras theorem formula, Using the Pythagoras theorm formula;

opposite² + adjacent² = hypotenuse²

let opposite  = 7 and let adjacent = 9   let the hypotenuse be x, if we calculate and x gives 11 then we will know it is a right-triangle

7² + 9² = x²

49 + 81 = x²

130 = x²

Take the square root of both-side

√130 =√ x²

11.40 = x

Therefore it is not a right triangle because the other side is 11 and not 11.40  when we apply the Pythagoras theorem rule on it

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %