What is the solution to the system of equations? 1/4x-1/2y=8, 1/2x+3/4y=-5

Option D: (8, -12) is the solution set for given system.

Step-by-step explanation:

Given that:

1/4x-1/2y=8 eq1

1/2x+3/4y=-5 eq2

Multiplying eq1 by 2 we get:

1/2x - y = 16 eq3

Now by subtracting eq3 from eq2 we get:

(1/2x+3/4y) - (1/2x - y ) = -5 -16

By simplifying:

3/4y + y = -21

By taking LCM to make denominator same:

3/4y + y*4/4 = -21

3+4 / 4y = -21

7/4y = -21

Multiplying both sides by 4/7 we get

y = -21 * 4/7

y = -12

Putting value of y in eq3

1/2x - (-12)= 16

1/2x + 12 = 16

1/2x = 16 - 12

1/2x = 4

Multiplying both sides by 2

x = 4*2

x = 8

So the solution set = (8, -12)

i hope it will help you!

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1e+27

step-by-step explanation: