What are the zeros of the polynomial function f(x)=x^3-5x^2-6x ?

Option C

The zeros of the polynomial function f(x) = x^3 - 5x^2 - 6x is x = 0 and x = -1 and x = 6

Given that polynomial function is f(x) = x^3 - 5x^2 - 6x

We have to find the zeros of polynomial

To find zeros, equate the given polynomial function to 0. i.e f(x) = 0

Taking "x" as common term,

Equating each term to zero, we get

Thus one of the zeros of function is x = 0

Now let us solve

We can rewrite -5x as -6x + x

Taking "x" as common from first two terms and -6 as common from next two terms

Taking (x + 1) as common term,

(x + 1)(x - 6) = 0

x + 1 = 0 and x - 6 = 0

x = -1 and x = 6

Thus the zeros of given function is x = 0 and x = -1 and x = 6

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.