If 14 g of a radioactive substance are present initially and 3 years later only 7 g remain, how much of the substance will be present after 4 yr?

5.56 g

We are given;

We need to determine the mass that will be present  after 4 years.

                                  = 4/3

Using the formula;

Therefore;

Remaining mass = 14 g × 0.5^4/3

                            = 5.56 g

Thus, the remaining mass after 4 years will be 5.56 g

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

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