Let f= 6(x+y)i + 6 sin(y)j,. find the line integral of f around the perimeter of the rectangle with corners (50) traversed in that order.

line integral =

333.04656

Step-by-step explanation:

F can be rewritten as

The path C on which we are going to evaluate the integral is

All the paths can be parametrized with parameter t (0≤ t≤ 1)

Parametrization of

r(t) = (5,0)+t((5,7)-(5,0)) = (5,0)+t(0,7) = (5,7t)

Parametrization of

r(t) = (5,7)+t((-3,7)-(5,7)) = (5,7)+t(-8,0) = (5-8t,7)

Parametrization of

r(t) = (-3,7)+t((-3,0)-(-3,7)) = (-3,7)+t(0,-7) = (-3,7-7t)

Parametrization of

r(t) = (-3,0)+t((5,0)-(-3,0)) = (-3,0)+t(8,0) = (-3+8t,0)

Finally

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: