If a function is defined by the formula y equals 2x + 1 + that domain is given by the set 3, 5, 7, 9 then which set represents the range of function

{7, 11, 15, 19}

Step-by-step explanation:

The function is defined by the formula y = 2x + 1 (1)

Now, domain of the function are given to be {3, 5, 7, 9}

Hence, from equation (1), at x= 3, y = 2 × 3 + 1 = 7

Now, at x = 5, y = 2 × 5 + 1 = 11

Again, at x = 7, y = 2 × 7 + 1 = 15

Finally, at x = 9, y = 2 × 9 + 1 = 19

Therefore, the range of the corresponding domain of this function is given to be {7, 11, 15, 19}. (Answer)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2