In acute triangle $abc$ we have $\cos a \cos b = \frac{1}{3}$ and $\sin a \sin b = \frac{1}{2}.$ if the area of triangle $abc$ is 1, what is the area of the orthic triangle? (the orthic triangle has vertices at the feet of the altitudes of the triangle.)

multiply length by height. multiply the length by the height, and then double the product. work out 10 x 10 results = 100 square inches, then work out 100 x 2 = 200. the answer is 200 square inches.

step-by-step explanation:

a. positive: 2 or 0; negative : 2 or 0; complex: 4or2or0

step-by-step explanation: