Arectangular garden has a walkway around it. the area of the garden is 4(3.5x+1.5). the combined area of the garden and the walkway is 5.5(6x+5). find the area of the walkway around the garden as the sum of two terms. simplified

The area of the walkway is 19x – 32.5

Given that, a rectangular garden has a walkway around it.  

The area of the garden is 4(3.5x+1.5)

The combined area of the garden and the walkway is 5.5(6x+5)

We have to find the area of the walkway around the garden as the sum of two terms.  

Now, we know that,

area of walkway = combined area of garden and walkway – area of garden

So, area of walkway = 5.5(6x + 5) – 4(3.5x + 15)  

Area = 33x + 27.5 – 14x – 60  

Area = 33x – 14x + 27.5 – 60  

Area = 19x – 32.5  

Hence, the area of the walkway is 19x – 32.5

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

answer: i'm great at algebra

~coco

step-by-step explanation: