Quiz 3
a bag contains 2 red marbles, 3 green marbles, and 4 blue marbles.
if we choose a marble, then another marble without putting the first one back in the bag, what is the
probability that the first marble will be green and the second will be red?
report a problem

1/12

Step-by-step explanation:

2 red marbles + 3 green marbles + 4 blue marbles = 9 marbles

First drawing:

You want a green marble out of 3 green marbles out of the total of 9 marbles.

p(green marble) = 3/9 = 1/3

Second drawing:

After drawing the green marble, there are 8 marbles left. There are 2 red marbles.

p(red marble) = 2/8 = 1/4

p(green then red) = 1/3 * 1/4 = 1/12

after simplifying it i got: -36.25 as my answer. hope that !