As an airplane rises, the outside temperature drops 3.6 degrees fahrenheit for each 1000 feat of elevation gain. suppose the outside temperature is 65 degrees fahrenheit on the ground and -43 degrees fahrenheit at cruising altitude. how high is the plane at cruising altitude?

30000 feet

Step-by-step explanation:

temperature on ground level = 65 °F

temperature at cruising altitude = -43 °F

total decrease in temperature = 65 - (- 43) = 65 + 43 = 108 °F

for each 1000 feet elevation temperature drops by 3.6 °F

and we have the total drop of temperature as 108 °F.

so,  Height of plane at cruising altitude = (drop in temperature/ 3.6) X 1000

                                                                 =

                                                                 = 30000 feet

$35.59 in pounds

step-by-step explanation:

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.